![In MathJax, how can I get the index of a cube root of a tall expression to be at the right level? - Mathematics Meta Stack Exchange In MathJax, how can I get the index of a cube root of a tall expression to be at the right level? - Mathematics Meta Stack Exchange](https://i.stack.imgur.com/da5Ey.png)
In MathJax, how can I get the index of a cube root of a tall expression to be at the right level? - Mathematics Meta Stack Exchange
How to write mathematical operators using LaTeX such as square, cube, roots, nth power, fraction, combinatorial operators, bar, integrals, and mathematical symbols - Quora
![I recently tried to prove that the cube root of 2 is irrational, and I am quite satisfied with my proof. What do you guys think? : r/mathmemes I recently tried to prove that the cube root of 2 is irrational, and I am quite satisfied with my proof. What do you guys think? : r/mathmemes](https://preview.redd.it/i-recently-tried-to-prove-that-the-cube-root-of-2-is-v0-wx2rkcnfkvgb1.png?auto=webp&s=4ed714de090bf8566b281abec4b8060fe9a63956)
I recently tried to prove that the cube root of 2 is irrational, and I am quite satisfied with my proof. What do you guys think? : r/mathmemes
![File:Lattice diagram of Q adjoin a cube root of 2 and a primitive cube root of 1, its subfields, and Galois groups.svg - Wikipedia File:Lattice diagram of Q adjoin a cube root of 2 and a primitive cube root of 1, its subfields, and Galois groups.svg - Wikipedia](https://upload.wikimedia.org/wikipedia/commons/thumb/b/b6/Lattice_diagram_of_Q_adjoin_a_cube_root_of_2_and_a_primitive_cube_root_of_1%2C_its_subfields%2C_and_Galois_groups.svg/2560px-Lattice_diagram_of_Q_adjoin_a_cube_root_of_2_and_a_primitive_cube_root_of_1%2C_its_subfields%2C_and_Galois_groups.svg.png)
File:Lattice diagram of Q adjoin a cube root of 2 and a primitive cube root of 1, its subfields, and Galois groups.svg - Wikipedia
What is the cube root of x raise to the power of 12? I really need a detailed and clear explanation on how to get the answer to [math]\sqrt[3]{x^{12}}[/math] or [math]\sqrt[3]{x}^{12}[/math]. Thank
![complex numbers - How do I show that $\frac{-1+\sqrt{3}i}{2}$ is the cube root of 1? - Mathematics Stack Exchange complex numbers - How do I show that $\frac{-1+\sqrt{3}i}{2}$ is the cube root of 1? - Mathematics Stack Exchange](https://i.stack.imgur.com/aF4D2.png)